Distance from Amarillo, TX to Savage, MN

Driving distance from Amarillo, TX to Savage, MN is 996 miles (1603 km). How far is it from Amarillo, TX to Savage, MN? It's a 16 hours 39 minutes drive by car. Flight distance is approximately 796 miles (1282 km) and flight time from Amarillo, TX to Savage, MN is 01 hours 36 minutes. Don't forget to check out our "Gas cost calculator" option. It will calculate cost of driving this particular distance. See the map below for the visual display of the upcoming road trip.

Driving distance
996 Miles
/
1603 Km
Driving distance
Gas consumption
39.84 Gallons
152.29 Litres
Gas consumption
Flight distance
796 Miles
/
1282 Km
Flight distance

How far is it from Amarillo, TX to Savage, MN?

To travel the distance from Amarillo, TX to Savage, MN, please, click on the map to see the route for the journey. "Gas Cost Calculator" tool is to your right. You can always modify it and make the number more applicable for your journey.

Book a Hotel for your trip to Savage, MN

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Last distance calculations