Distance from Lake Charles, LA to Sandy, UT

Driving distance from Lake Charles, LA to Sandy, UT is 1555 miles (2502 km). How far is it from Lake Charles, LA to Sandy, UT? It's a 27 hours 41 minutes drive by car. Flight distance is approximately 1265 miles (2035 km) and flight time from Lake Charles, LA to Sandy, UT is 02 hours 32 minutes. Don't forget to check out our "Gas cost calculator" option. It will calculate cost of driving this particular distance. See the map below for the visual display of the upcoming road trip.

Driving distance
1555 Miles
/
2502 Km
Driving distance
Gas consumption
62.20 Gallons
237.69 Litres
Gas consumption
Flight distance
1265 Miles
/
2035 Km
Flight distance

How far is it from Lake Charles, LA to Sandy, UT?

To travel the distance from Lake Charles, LA to Sandy, UT, please, click on the map to see the route for the journey. "Gas Cost Calculator" tool is to your right. You can always modify it and make the number more applicable for your journey.

Book a Hotel for your trip to Sandy, UT

Choose a place to stay while traveling from Lake Charles, LA to Sandy, UT. We also offer Car Rental widget for your particular journey. There are lots of options to choose from. Give it a try.

Last distance calculations