Distance from Seymour, IN to Sartell, MN

Driving distance from Seymour, IN to Sartell, MN is 731 miles (1176 km). How far is it from Seymour, IN to Sartell, MN? It's a 12 hours 01 minutes drive by car. Flight distance is approximately 626 miles (1007 km) and flight time from Seymour, IN to Sartell, MN is 01 hours 15 minutes. Don't forget to check out our "Gas cost calculator" option. It will calculate cost of driving this particular distance. See the map below for the visual display of the upcoming road trip.

Driving distance
731 Miles
/
1176 Km
Driving distance
Gas consumption
29.24 Gallons
111.72 Litres
Gas consumption
Flight distance
626 Miles
/
1007 Km
Flight distance

How far is it from Seymour, IN to Sartell, MN?

To travel the distance from Seymour, IN to Sartell, MN, please, click on the map to see the route for the journey. "Gas Cost Calculator" tool is to your right. You can always modify it and make the number more applicable for your journey.

Book a Hotel for your trip to Sartell, MN

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Last distance calculations